what are the differents between "name" and "type" in roslaunch for nodes?
<launch>
<master auto="start"/>
<node pkg="tf" type="static_transform_publisher" name="fake_localize" args="0 0 0 0 0 0 map odom 10"/>
</launch>
Originally posted by Mohsen Hk on ROS Answers with karma: 139 on 2013-05-02
Post score: 5
Type is the file you want to launch in the package whereas the name is a unique identifier for your node.
In your example it will launch static_transform_publisher in package tf with name of the node as fake_localize.
http://www.ros.org/wiki/roslaunch/XML/node
Originally posted by rohan with karma: 358 on 2013-05-02
This answer was ACCEPTED on the original site
Post score: 13
Comment by Mohsen Hk on 2013-05-02:
tnx for your link. for complete the answre, for example in my launch file >> the "fake_localize"(NAME) node is uniqe arbitrary name, (you can see in rxgraph!) using the "static_transform_publisher" (TYPE) executable from the "tf" package.
Comment by rohan on 2013-05-02:
Yes that's right!
The easiest way to find out what to initialize in the type is to go to your CMakeLists.txt. Find the line that says something like add_executable(blah_blah src/whatever.cpp) then blah_blah is the type. Another way is to cd to your /devel/lib/ folder, dig into your package and there you will see the executables(probably, in green).
Originally posted by oogabooga with karma: 51 on 2014-12-04
This answer was NOT ACCEPTED on the original site
Post score: 4
Comment by Fenglong on 2022-04-14:
Thanks for the answer. While using C++ the "type" in launch file should be the name of the target in CMakeLists.txt, but when using Python it should be the "XXX.py", is that correct?