Hi, is it possible to load all yaml-files in an folder? Like:
<rosparam folder="$(find parameter)/my_params/" />
Originally posted by Tobias Neumann on ROS Answers with karma: 179 on 2014-09-05
Post score: 0
1 Answer
$\begingroup$
$\endgroup$
According to the roslaunch doc it shouldn't work: "The tag can either reference a YAML file or contain raw YAML text." You could try writing a small node that takes a path and uses rosparam.load_file()
Originally posted by Chrissi with karma: 1642 on 2014-09-05
This answer was ACCEPTED on the original site
Post score: 0
Original comments
Comment by Tobias Neumann on 2014-09-05:
Yes I thought about that too, but I thought there might be an easier solution.
But if I write a node, how can I guarantee that all parameters are loaded before my launch file startes the next node that is depending on them?
Comment by Chrissi on 2014-09-05:
One solution would be to offer a service once all parameters are set and to make the other nodes wait for that service to become available before doing anything.
Comment by Tobias Neumann on 2014-09-05:
Mh, that would work, but needs more codeing than adding a line for each yaml file in the launch file :(
There might be an different way? Would be a cool feature for rosparam
Comment by Chrissi on 2014-09-06:
We are actually following a database approach to that. In my project we are using mongodb and have a tool that reads yaml files, saves the found parameters in the datacentre and also sets them on the parameter server. You can have a look at this