The orientation angles will be provided in the Earth frame (global or world frame is more appropriate). It is pretty much impossible to provide a frame orientation with angles with respect to that same frame.
Then, given some acceleration $a_b$ in the body frame, you can find the acceleration in the world frame $a_w$ by pre-multiplication with the rotation matrix $R$.
$a_w = R a_b$
If you assume a typical roll-pitch-yaw sequence, then this will look like:
$\begin{bmatrix} a_{w,x} \\ a_{w,y} \\ a_{w,z} \end{bmatrix} = \begin{bmatrix} c_\psi c_\theta & -s_\psi c_\phi + c_\psi s_\theta s_\phi & s_\psi s_\phi + c_\psi s_\theta c_\phi \\ s_\psi c_\theta & c_\psi c_\phi + s_\theta s_\psi s_\phi & -c_\psi s_\phi + s_\theta s_\psi c_\phi \\ -s_\theta & c_\theta s_\phi & c_\theta c_\phi \end{bmatrix} \begin{bmatrix} a_{b,x} \\ a_{b,y} \\ a_{b,z} \end{bmatrix}$
Where $c_x = \cos x$ and $s_x = \sin x$.
Of course, you can expand this to specify the x-y-z components of the world frame acceleration as individual equations as you mentioned:
$a_{w,x} = f(a_b, \phi, \theta, \psi)$
$a_{w,y} = g(a_b, \phi, \theta, \psi)$
$a_{w,z} = h(a_b, \phi, \theta, \psi)$
Note that I am using the convention where $\phi$ is roll (about x-axis), $\theta$ is pitch (about y-axis), and $\psi$ is yaw (about z-axis).
When the rotation sequence roll, pitch, yaw is applied, each rotation occurs with respect to a world frame axis. We could get the same final result by applying a yaw, pitch, roll sequence but about each new axis. This latter method is more intuitive when visualizing roll-pitch-yaw (or rather Euler angle) rotations.
Here is a figure to clarify the rotation sequence in case it helps. The world frame is shown in black, the body frame in red-green-blue, and intermediary frames during the "intuitive" rotation sequence are included in grey.
