3
$\begingroup$

I have this close loop transfer function: close loop transfer

It overshoots, but why? The poles are placed such that that the damping = 1, so why the overshoot?

$\endgroup$
1
$\begingroup$

The zero in the transfer function has an anticipatory effect that you can easily see as an overshoot.

However, since the zero is in the left half of the s-plane, you can consider the pole-zero cancellation as a suitable technique to get rid of that zero.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.