Quadcopter forward speed

Question

I am trying to better understand the dynamics of forward flight in multirotors.

Assuming I have a quadcopter with 4 motor/propeller combinations capable (each) of a propeller pitch speed of, say, SpeedMax= 100 mph.

In forward horizontal flight, the quadcopter will pitch down at a certain angle, let's say AlphaP, from horizontal. If AlphaP is, say, 45 degrees, and drag is neglected, wouldn't the quadcopter be capable of a max theoretical speed of sin (45)* SpeedMax ~ 70Mph?

Also, seems to me AlphaP cannot go all the way to 90 degree (quadcopter flying like a plane), as at that point the propellers would not produce any upward thrust to maintain the copter aloft given there is no wing loading as available in a plane. If drag was to be neglected, what factors would the optimum AlphaP be depended on, and what would that angle be, for maximum speed?

Answer 1

As you said, as AlphaP increases, the amount of upward thrust decreases, and when AlphaP = Forget about speed. This idea that each propeller is capable of 100mph isn't that helpful. The problem is that the thrust produced by the propellers will be a function of speed. The faster they are traveling through the air, the less thrust they'll produce. Think instead about thrust. How much thrust are the propellers capable of?

90º, there's no upward thrust at all. Your tilt angle, AplhaP will be limited by the upward thrust needed to keep the quadcopter aloft. the amount of upward thrust produced is proportional to cos(AlphaP).

If all 4 propellers together produce 20N, and your Quadcopter weighs 10N, then to stay aloft:

• cos(AlphaP)*20N >= 10N
• cos(AlphaP) >= 0.5
• Alpha <= invcos(0.5)
• Alpha <= 60º

Now the forward thrust produced will be sin(60º)*20N = 0.866*20N = 17.3N. What speed does this relate to? You can't neglect drag here. The quadcopter will accelerate until the drag equals 17.3N.

But of course, it's not that simple. What's confounding this is that the thrust produced at speed will be less than that produced when stationary. A very rough first approximation is to think of the power output of the propellers.

• power = force * speed

Double the speed means half the thrust. But it's not that simple either. Generally, when you do these simple calculations, I would divide the results by 4 to get a more realistic estimate of the maximum speed.

Answer 2

Great question! And, yes props develop acceleration, but neglecting friction does not mean speed is infinite, because the thrust from the prop is a function of the angle of attack which changes as speed increases. At some angle, with maximum power applied, lift=weight and forward thrust=drag. It's not a simple problem to solve. At the prop tip the effective airspeed in hover is r*w (radius of prop x angular velodicy in radians/sec (RPM/10)). In forward, tilted flight, the effective airspeed at the prop tip is the sum of the propeller speed vector, plus the relative movement of the quad at the forward tilt angle. My point is, this is a VERY VERY complex problem to solve. You can do it but you need to be very strong in math, geometry and maybe even calculus and Excel. I've done calculations like this using the Iterate feature in Excel. I broke the problem down into tiny pieces (small sections of the prop) and solved the aerodynamics for each little piece of the prop, and then added them all up for the total effect. LOTS of work. Best bet is probably to survey some data from quad racers in online forums and make some educated guesses from that. Good Luck. (BTW, I found this thread because I'm looking for exactly the same answer). But I'm looking for it so that I can understand the difference in lift on the advancing blade versus the retreating blade. The advancing blade sees a higher airspeed, but it also has a smaller angle of attack because the airframe is tilted forward. Do these two effects cancel each other out?.

Answer 3

With my rudimentary knowledge of aerodynamics, your calculation of forward horizontal velocity sounds OK. I'm sure other people can shed more light on the practical constraints.

About the max alphaP angle, here's what I think: Say your copter can produce F Newton upward thrust. And say your copter weighs x Kg. Then your max angle for alphaP will be governed by:

 F*cos(maxAlphaP) = x*g     //cos or sine alphaP, depending upon how you measure the angle.

Answer 4

Well if i understand you question which im not sure if i do your asking how to make the copter move and the answer to that is lower the power slightly on the direction you want to move sorry for being unhelpful