-1
$\begingroup$

for a DC motor, when the torque or load is small, the DC motor rotation speed is fast. When load becomes bigger, the speed slows down. But what if the load exceeded the stall torque, and maybe cause the motor to rotate in reverse? In this case, what will the motor current be and what will happen? In addition, is there any type of motor that can handle overload torque easily or still gives you "stall torque" or "max torque" no matter how much torque you apply?

When the applied torque exceeds the stall torque, then the motor will rotate in reverse, so does the DC motor become a generator? But the applied power is still there, so maybe the newly generated voltage will actually reduce voltage supply and hence reduce the "stall current"? Also, what about the combined torque when "stall torque" was exceeded?

$\endgroup$
  • 1
    $\begingroup$ what will be the current .... depends on the motor and on the power supply ..... handle overload torque easily .... it is unclear what you are asking $\endgroup$ – jsotola Jan 24 at 20:37
  • $\begingroup$ Forcing it to turn in the opposite direction to the applied voltage is equivalent to reversing the power supply while it's being turned forward. Both actions are braking. Looks the same as this question electronics.stackexchange.com/questions/236003/… $\endgroup$ – user1318499 Jan 25 at 21:28

Your Answer

By clicking "Post Your Answer", you acknowledge that you have read our updated terms of service, privacy policy and cookie policy, and that your continued use of the website is subject to these policies.

Browse other questions tagged or ask your own question.