2
$\begingroup$

Is there a possibility of making robots which utilise raw materials to create more versions of themselves? Clarifying the point what I would like to ask is that whether there are are any projects or research on robots that can reproduce!!!

$\endgroup$
  • $\begingroup$ Ever heard of the reprap project? $\endgroup$ – Paul Jan 8 '17 at 22:32
  • $\begingroup$ Umm no could send me the site $\endgroup$ – user39460 Jan 9 '17 at 2:27
  • 2
    $\begingroup$ Welcome to Robotics user39460, but I'm afraid that speculative questions like this really aren't a good fit for a stack exchange site. We prefer practical, answerable questions based on actual problems that you face. Take a look at How to Ask and tour for more information on how stack exchange works. Also, the Robotics question checklist has good advice on how to write a good question. $\endgroup$ – Mark Booth Jan 10 '17 at 10:38
  • 2
    $\begingroup$ If that is the crux of your question then the answer is a definite no. People will cite reprap, or nano replicating sites, and claim self-replication. The reality is that going from raw materials, to the state in which specific robot construction or replication can take place, requires an enormous amount of processing that is generally unaccounted for by the claims of self-replication. As a simple example, consider how a spool of ABS plastic is created in order to manufacture a single 3D printed part. No part of the reprap project creates the spool of material from raw materials. $\endgroup$ – SteveO Jan 11 '17 at 3:49
  • 1
    $\begingroup$ Sorry @user39460 even specifying it to be current research projects doesn't make it a good fit for a stack exchange site. Any answers that you might get would soon be out of date, so a simple google search would almost always be more useful than answers on this question. If you wish to discuss this more, feel free to bring it up in Robotics Chat when you have a reputation of 20. $\endgroup$ – Mark Booth Jan 11 '17 at 10:13

Browse other questions tagged or ask your own question.