Timeline for DC motor direct loading
Current License: CC BY-SA 3.0
13 events
| when toggle format | what | by | license | comment | |
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| Sep 14, 2014 at 5:53 | answer | added | David Cary | timeline score: 0 | |
| Apr 7, 2014 at 11:36 | history | tweeted | twitter.com/#!/StackRobotics/status/453134280924094464 | ||
| Jan 15, 2014 at 5:37 | answer | added | user3150208 | timeline score: 0 | |
| S Jan 14, 2014 at 19:51 | history | suggested | Diego C Nascimento | CC BY-SA 3.0 |
added tag, grammar, thanks is done by upvoting
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| Jan 14, 2014 at 12:34 | review | Suggested edits | |||
| S Jan 14, 2014 at 19:51 | |||||
| Oct 15, 2013 at 12:12 | answer | added | OricTosh | timeline score: 1 | |
| Oct 11, 2013 at 9:34 | comment | added | SekaiCode | I am just curious how the orientation of the load as well as the motor affect the application. Of course i can place the motor horizontally and use the gear and shaft(convert the motion direction and adjust torue:speed) to do the same thing, but this is not what i want to know. | |
| Oct 11, 2013 at 9:30 | comment | added | SekaiCode | sorry for late reply, i know how the stall toque and the continuous toque affect the selection of motor. 1 RPM is just an arbitrarily number. What i want to know is the calculation of the toque(stall and continuous).My physics is very bad, i don't know how to calculate toque in this kind of vertical setup. All information i found on the web always lead me to the torque calculation for motor driving wheels(which is simply the tangential force multiply the moment arm). Thank you. | |
| Oct 9, 2013 at 20:59 | comment | added | TimWescott | To complicate things further, the faster you want to spin it up (or down), the more torque you need. You also need to choose between direct drive (which is hugely inefficient for 1RPM) or some sort of gear- or belt drive, which requires more mechanical 'stuff'. | |
| Oct 7, 2013 at 21:41 | comment | added | Aerophilic | SekaiCode, I think to get a good answer for you, You'll need to provide more information. The reality is that if you mount a motor w/ the disc as you describe, at "rest" there would be no torque required by the motor at all to keep it "in place". However, if you want to know how much torque would be necessary to "spin it up" and keep it going... that is a much more complicated answer. In short though, to get it "started" you would need a motor strong enough to get over the initial inertia + friction. To have it "keep going" you would need to overcome friction. What are you looking for? | |
| Oct 7, 2013 at 18:45 | comment | added | Ian | Are you asking about the force of gravity on the motor's bearings? | |
| Oct 5, 2013 at 15:11 | review | First posts | |||
| Oct 5, 2013 at 23:34 | |||||
| Oct 5, 2013 at 14:56 | history | asked | SekaiCode | CC BY-SA 3.0 |